Penjelasan dengan langkah-langkah:
[tex] \frac{2 \sqrt{3} - \sqrt{6} }{ \sqrt{8} - \sqrt{2} } \\ \frac{2 \sqrt{3} - 6 }{ \sqrt{8} - \sqrt{2} } \times \frac{ \sqrt{8} + \sqrt{2} }{ \sqrt{8} + \sqrt{2} } \\ \frac{2 \sqrt{24} + 2 \sqrt{6} - 6 \sqrt{8} - 6 \sqrt{2} }{8 - 2} \\ \frac{4 \sqrt{6} + 2 \sqrt{6} - 12 \sqrt{2} - 6 \sqrt{2} }{6} \\ \frac{6 \sqrt{6} - 18 \sqrt{2} }{6} \\ \sqrt{6} - 3 \sqrt{2} [/tex]
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Penjelasan dengan langkah-langkah:
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[tex](2\sqrt3 - \sqrt6)(\sqrt8 - \sqrt2)=[/tex]
[tex]= 2\sqrt3 (\sqrt8 - \sqrt2)- \sqrt6 (\sqrt8 - \sqrt2)[/tex]
[tex]= 2\sqrt{24} - 2\sqrt 6 - \sqrt{48} + \sqrt{12}[/tex]
[tex]= 2\sqrt{4\times 6} - 2\sqrt 6 - \sqrt{16\times 3} + \sqrt{4\times 3}[/tex]
[tex]= 2(2)\sqrt{ 6} - 2\sqrt 6 - 4\sqrt{3} + 2\sqrt{3}[/tex]
[tex]= 4\sqrt{ 6} - 2\sqrt 6 - 4\sqrt{3} + 2\sqrt{3}[/tex]
[tex]= 2\sqrt6 - 2\sqrt 3\\[/tex]
[tex]= 2 (\sqrt6 - \sqrt3)[/tex]
[answer.2.content]
